17x^2-25x-1940=0

Solution for 17x^2-25x-1940=0 equation:

17x^2-25x-1940=0

a = 17; b = -25; c = -1940;
Δ = b2-4ac
Δ = -252-4·17·(-1940)
Δ = 132545
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{132545}=\sqrt{49*2705}=\sqrt{49}*\sqrt{2705}=7\sqrt{2705}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-25)-7\sqrt{2705}}{2*17}=\frac{25-7\sqrt{2705}}{34}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-25)+7\sqrt{2705}}{2*17}=\frac{25+7\sqrt{2705}}{34}
$